48÷2(9+3) = ???

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
 
team 288.

[h3]48÷2(9+3) = [complete the parenthesis first]
[/h3]48÷2(12) = [at this point, you have both division and multiplication, you have to evaluate from left to right]

24(12) = 288 [therefore, 288]
 
team 288.

[h3]48÷2(9+3) = [complete the parenthesis first]
[/h3]48÷2(12) = [at this point, you have both division and multiplication, you have to evaluate from left to right]

24(12) = 288 [therefore, 288]
 
Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
 
Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
 
Originally Posted by Iron Mike

king krux should be suspended for trolling
Click to expand...
Oh yeah?


Again...



If you still don't get it then I don't know anymore.

You should really call your school and ask them to explain.
 
Originally Posted by Iron Mike

king krux should be suspended for trolling
Click to expand...
Oh yeah?


Again...



If you still don't get it then I don't know anymore.

You should really call your school and ask them to explain.
 
Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...



I posted this link over 40 pages ago... they don't get it. I agree with biggie62's rationale too.
 
Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...



I posted this link over 40 pages ago... they don't get it. I agree with biggie62's rationale too.
 
Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...
Quoted  because I know these Math trolls will ignore this again.
 
Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...
Quoted  because I know these Math trolls will ignore this again.
 
Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2
 
Originally Posted by do work son

Originally Posted by GreenRanger

Originally Posted by dland24

Can anyone please show me ANY source which EXPLICITLY states that the first part of the order of operations is not just whats inside the parentheses, but anything connected to them as well?  
Click to expand...


"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2
 
Again, just so its even more clear...

The distributive property of multiplication CLEARLY states that the 2(9+3) is an entire term and CANNOT be broken up. 2(9+3) follows the distributive property which can be rewritten as (2*9+2*3). Let me repeat the 2 outside of the parenthesis follows the distributive property of multiplication and must be factored and simplified before performing any other operations on it.

So this can be rewritten as:
48 / (2*9 + 2*3)

Which leaves us with

48 / 24 = 2

Answer = 2.

Lastly for those using Google or any other online calculator. These do not understand many theorems or properties so you must explicitly explain what you mean. There is a difference between 48 / 2 *(9+3) and 48 / 2(9+3). The first notation reads 48 / 2 * 1(9+3) while the second reads 48 / (2*9+2*3). Be very careful with your signs.
 
Again, just so its even more clear...

The distributive property of multiplication CLEARLY states that the 2(9+3) is an entire term and CANNOT be broken up. 2(9+3) follows the distributive property which can be rewritten as (2*9+2*3). Let me repeat the 2 outside of the parenthesis follows the distributive property of multiplication and must be factored and simplified before performing any other operations on it.

So this can be rewritten as:
48 / (2*9 + 2*3)

Which leaves us with

48 / 24 = 2

Answer = 2.

Lastly for those using Google or any other online calculator. These do not understand many theorems or properties so you must explicitly explain what you mean. There is a difference between 48 / 2 *(9+3) and 48 / 2(9+3). The first notation reads 48 / 2 * 1(9+3) while the second reads 48 / (2*9+2*3). Be very careful with your signs.
 
Originally Posted by TheHealthInspector

Originally Posted by do work son

Originally Posted by GreenRanger



"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2
Click to expand...
Show me a Math problem with a Ã·(2(9+3)) 
This is just ridiculous. It's like saying divide AND multiply. 
 
Originally Posted by TheHealthInspector

Originally Posted by do work son

Originally Posted by GreenRanger



"That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy"


http://www.purplemath.com/modules/orderops2.htm
Click to expand...

the examples on that website pretty much seal the deal. team 2 ftw
Click to expand...

that is straight up bull

like i said 10 pages ago, you guys are trying to misconstrue our common understanding of... 2(9+3)... aka... 2*(9+3)... aka... (2)(9+3)... aka... (2)*(9+3)... in order to mean something that its not... ie (((((2(9+3))))))

theres 5 other concepts in PEmDAS that follow ALL rules ALL the time, but because of this particular placement, yall want to make it out to be peMdas

NO OTHER CONCEPT BREAKS THE RULES LIKE THAT, yall are misconstruing placement of the 2
Click to expand...
Show me a Math problem with a Ã·(2(9+3)) 
This is just ridiculous. It's like saying divide AND multiply. 
 
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